Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 28, the sum of the squares is 65, and the sum of the cubes of the numbers is 407.

x + y = 11

Step-by-step explanation:

xy = 28

x² + y² = 65

x³ + y³ = 407

(x + y)(x² - xy + y²) = x³ + y³

(x + y)(x² + y² - xy) = x³ + y³

(x + y)(65 - 28) = 407

37(x + y) = 407

x + y = 407÷37

x + y = 11

the answer is simply just 6n add the two together as they have an n