Hint: To be collinear, show that : AB t
SP SQ
यदि P र Q दुई बिन्दुहरू हुन् जसका निर्देशाङ्कहरू क्रमशः (ark, 2at) र (1) र S बिन्दु (a, 0) भए
( 4 )
बाट मुक्त छ भनी देखाउनुहोस् ।
IP and Q are two points whose co-ordinates are (at', 2at) and (a/t^2 , 2a/t)
respectively and S is the point
(a,0). Show that(1/SP +1/SQ)
SO
is independent of t.
ANSWERS

As the points are collinear, the slope of the line joining

any two points, should be same as the slope of the line joining two other

points.

Slope of the line passing through points (x

1

,y

1

) and (x

2

,y

2

) =

x

2

−x

1

y

2

−y

1

So, slope of the line joining (p,0),(0,q)= Slope of the line joining

(0,q) and (1,1)

0−p

q−0

=

1−0

1−q

−

p

q

=1−q

Dividing both sides by q,

−

p

1

=

q

1

−1

=>

p

1

+

q

1

=1

answer is 1 hope this helps you helps so like this

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

the correct answer is c