In manufacturing processes, it is of interest to know with confidence the proportion of defective parts. Suppose that we want to be reasonably certain that less than 4% of a company’s widgets are defective. To test this, we obtain a random sample of 250 widgets from a large batch. Each of the 250 widgets is tested for defects, and 6 are determined to be defective, based upon the manufacturer’s standards. Using α = 0.01, is this evidence that less than 4% of the company’s widgets are defective? State the hypotheses, list and check the conditions, calculate the test statistic, find the p-value, and make a conclusion in a complete sentence related to the scenario.

The calculated value Z =   1.3114 < 2.576 at 0.01 level of significance

null hypothesis is accepted

The  evidence that less than 4% of the company’s widgets are defective

Step-by-step explanation:

Step(i):-

Given Population proportion

                                           P = 4% = 0.04

Given sample proportion

Null hypothesis :- P < 0.04

Alternative Hypothesis :  P ≠ 0.04

Step(ii):-

Test statistic

                   Z = - 1.3114

              |Z| = | - 1.3114|

The tabulated value Z = 2.576

The calculated value Z =   1.3114 < 2.576 at 0.01 level of significance

null hypothesis is accepted

The  evidence that less than 4% of the company’s widgets are defective

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !