Question 22
2 pts
A helicopter is taking off from the roof of a 47 foot tall building at a rate of 72
feet per second. How far off the ground would the helicopter be if it started its
takeoff 6 seconds ago.

479 ft

Step-by-step explanation:

speed = 72 ft/sec

speed = distance/time

distance = speed * time

In 6 seconds, time = 6 sec

distance = speed * time

distance = 72 ft/sec * 6 seconds

distance = 432 ft

The helicopter travels to a height of 432 ft above the roof of the building in 6 seconds, but since it started at 47 ft above ground, the total distance above ground after 6 seconds is

47 ft + 432 ft = 479 ft

479 ft

sine

step-by-step explanation:

the answer would be c:   ax + b = ax + c

step-by-step explanation: