The diagram (picture) shows the speed-time graph of a body moving in a straight line. (a) Calculate he acceleration of the body during the first 15 seconds.
(b) Calculate the distance moves by the body in the first 40 seconds of its motion.
(c) Given that the body decelerate at 1.25 m/s

Below.

Step-by-step explanation:

(a)

The acceleration = the slope of the graph (change of velocity / time)

= 25/15

= 1.67 m/s/s.

(b)

The distance moved = the area under the graph for the first 0 seconds,

= area of the first triangle + area of the rectangle with height 25 and length (40 - 15)

= 1/2 * 15 * 25  + (40-15) * 25

= 187.5 + 625

= 812.5 m.

(c). ? what is the question?

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.

probably .5

i can on others if necessary.