The product of two consecutive even integers is 168. Find the integers. Please explain

12 and 14

-12 and -14

Explanation:

let the first even integer be

x

So the second consecutive even integer will be

x

+

2

Since the given product is 168 ,the equation will be as follows:

x

⋅

(

x

+

2

)

=

168

x

2

+

2

⋅

x

=

168

x

2

+

2

⋅

x

−

168

=

0

Your equation is of the form

a

.

x

2

+

b

⋅

x

+

c

=

0

Find the discriminat

Δ

Δ

=

b

2

−

4

⋅

a

⋅

c

Δ

=

2

2

−

4

⋅

1

⋅

(

−

168

)

Δ

=

676

Since

Δ

>

0

two real roots exist.

x

=

−

b

+

√

Δ

2

⋅

a

x

'

=

−

b

−

√

Δ

2

⋅

a

x

=

−

2

+

√

676

2

⋅

1

x

=

12

x

'

=

−

2

−

√

676

2

⋅

1

x

'

=

−

14

Both roots satisfy the condition being even integers

First possibility : two consecutive positive integers

12 and 14

Second possibility : two consecutive negative integers

-12 and -14

i think asking google will you get the answer to that question