What is an equation in slope-intercept form of the line that passes through (6, 10) and is parallel to the graph of y=1/3x−1? Here are the answer choices:
A: y−10=1/3(x−6)
B: y=1/3x+8
C: y−10=−3(x−6)
D: y=−3x+28

B

Step-by-step explanation:

sope intercept form: (y=mx+b)

m = slope

m = 1/3 (slope of parallel lines are the same)

10 = 1/3(6)+b

10 = 2+b

b = 8

write with slope and b

y = 1/3x+8

The answer is B

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x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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