A line has a slope of - and passes through point
What is the equation of the line?

y-y1 = m(x-x1)

Step-by-step explanation:

if the slope = m

and it passes through the point (x1, y1)

you use the formula y-y1 = m(x-x1)

y-y1 = m(x-x1)

Step-by-step explanation:

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

[2, 2.5)

(2.5, 3]

step-by-step explanation:

i think its these two not sure [2, 2.5)

(2.5, 3]