Find the equation of the line through (-4,-1) and parallel to y = -1/2x +1 in slope- intercept form.
d) y = -1/2x - 3
c) y = 1/2x + 3
b) y = 2x - 3
a) y = -1/2x + 3

Step-by-step explanation:

Let the equation of the line be y = mx + c

since the line is parallel to y = -1/2x + 1, the two lines have the same gradient.

therefore, m = -1/2

sub (-4, -1):

-1 = -1/2(-4) + c

c = -3

therefore equation of the line is y = -1/2x - 3

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step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.