The length of a rectangle 2 less than 2 times the width. The perimeter is 116ft. Find the length and width.

w = 20 l = 38

Step-by-step explanation:

l = 2w - 2 (based on given info)

p = 2l + 2w (formula for perimeter)

p = 116 (given)

116 = 2l + 2w

116 = 2(2w-2) + 2w (substitute in l)

116 =‘ 4w-4 + 2w

116 = 6w-4

w=20

l=2(20) - 2 = 38

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

thats not a system of equations, that is a solution