4. X varies directly with the square of y, where x>0, and y >0. If x= 3 when y = 5, then what is the value
ofy when x= 48?

The value of y, when x = 48 is y = 12/5

Step-by-step explanation:

The given parameters are;

x is directly proportional to y

Where x > 0, y > 0

For x = 3. y = 5

Therefore, we have;

x ∝ a·y²

For ,x = 3, when y = 5, we have;

3 = a × 5² = 25·a

∴ a = 25/3

When x = 48, we have;

48 = 25/3×y²

y² = 3/25 × 48 = 144/25

y = √(144/25) = 12/5

y = 12/5

The value of y, when x = 48 is y = 12/5.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: