The sum of two consecutive even integers is 48 less than 3 times the largest integer. Find both integers algebraically.

Step-by-step explanation:

Let the integers be:

Then we have:

Solving for n:

So the numbers are 44 and 46

the answer is 11.2 (i know i’m late)

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.