A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. y=-16x^2+242x+73

t = 15.42 s

Step-by-step explanation:

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.

We ned to find the time when the rocket will the ground. For this, y = 0

It is a quadratic equation whose solution is given by :

Here, a = -16, b = 242 and c = 73

Neglecting negative value.

So, it will hit the ground in 15.42 s.

i need the options

step-by-step explanation:

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