1. What are the vertex and axis of symmetry of the parabola? y = x2 + 4x + 3 hint: to find the axis of symmetry use x =
-(b)/2la)
axis of symmetry : x = 2
verter : (2, -1)
axis of symmetry : x = -2
vertex : (-2,-1)
axis of symmetry : x = -2
vertex : (-2, 1)

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

p = 6s

step-by-step explanation: