Solve Algebraically 2^3-x=565

x  =  3  − log  565/  log  2  =  −  6.142107057

Step-by-step explanation:

2^3-x =565

Log 2^3-x =  log  565

(3-x) times log 2 = log 565

3 −  x  =  log  565 / log  2

3  −  log  565 / log  2  =  x

x  =  3  − log  565/  log  2  =  −  6.142107057

idk

step-by-step explanation:

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions