What is the value of x2 + (2y) ÷ (2w) + 3z for w = 2, x = 5, y = 8, and z = 3?

To find the value of x² + (2y) ÷(2w) +3z , first we substitute the values of w, x, y and z

5² + 2(8) ÷ 2(2) + 3(3)

To simplify this further, we have to apply the rule of BODMAS

(Applying the rule of BODMAS simply means when you have an equation, if its having bracket, you have to remove the bracket first, then you move to powers then you proceed to dividing then subtraction and then addition)

5² + 2(8) ÷ 2(2) + 3(3)

=25 +16 ÷ 4 +9

=25 + 4 +9

=38

Therefore the value of x² + (2y) ÷(2w) +3z is 38

(1/x + 1)^2 + 6 (1/x + 1) +5