At noon, a tank contained 5 cm of water. After several hours, it contained 4 cm of water. What is the percent decrease of water in the tank?

20%

Step-by-step explanation:

Given parameters:

Initial volume of water = 5cm³

New volume of water = 4cm³

Unknown:

Percentage decrease of water in the tank = ?

Solution:

To find the percentage decrease;

  Percentage decrease  = x 100

 Percentage decrease  = x 100  = 20%

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58