A pizza parlor has a choice of 10 toppings for its pizzas. From these 10 toppings, how many different 7-topping pizzas are possible?

what are the choices?

Step-by-step explanation:

if there are none then i'll say 331

To solve for the number of different possible pizzas with 7 toppings out of 10 and the arrangement of these toppings is not important, therefore we use the combination formula.

The formula for combination is:

n C r = n! / r! (n – r)!

where,

n = is the total number of toppings = 10

r = the number of toppings in a pizza = 7

Substituting the values into the equation:

10 C 7 = 11! / 7! (11 – 7)!

10 C 7 = 11! / 7! * 4!

10 C 7 = 329

Therefore there are a total different 329 (or 330) pizzas with 7 different combinations toppings.

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

answer:

your answer is: c. 196 7/8 in^3.