What are the solutions of the quadratic equation? 2 x^2 – 16 x + 32 = 0

X=4,4

Step-by-step explanation:

2 x^2 – 16 x + 32 = 0

2(x^2-8x+16)=0

X^2-(4+4)X+16=0

x^2-4x-4x+16=0

x(x-4)-4(x-4)=0

(x-4)(x-4)=0

X=4,4

So the solution is X=4,4

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation:

triangle and cube

step-by-step explanation: