Gumballs cost $0.50 each and jawbreakers cost 0.30 each bob has $3.00 to spend Create an inequality that represents the number of gumballs and jawbreakers Bob can buy

a0.50 + b0.30 ≤ $3.00

Step-by-step explanation:

From the question, we have:

Gumballs cost per unit = $0.50

Jawbreakers cost = $0.30

Total budget of Bob = $3.00

Let a represents the number of Gumballs Bob can buy.

Let b represents the number of jawbreakers Bob can buy.

Therefore, inequality that represents the number of gumballs and jawbreakers Bob can buy can be given as follows:

a0.50 + b0.30 ≤ $3.00

The inequality implies that total amount Bob can spend on both gumballs and jawbreakers can be less or equal to $3.00 but cannot be greater than $3.00.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

step-by-step explanation:

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