Draw triangle ABC by first drawing segment BC six inches long. Then draw a 60° angle at vertex B and a 60° angle at vertex C. Extend the segments so that they intersect at point A.

Step-by-step explanation:

Given that segment BC is the base of the triangle, this drawing shows that triangle ABC is an equilateral triangle.

Since;

<B = <C = 60°

Then,

<A + <B + <C =

<A + 60° + 60° =

<A = -

    = 60°

Thus,

AB = BC = AC = 6 inches

The construction is attached to this answer.

why can't you?

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3