a mass of 25kg on a ramp at an angle of inclination 30 degrees to the horizontal, is oulled with a force of 75 kg an angle of 20 degrees to the ramp what is the frictional force if it is pulled up the ramp at constant speed

Decompose the forces into components that are parallel or perpendicular to the plane. Then the fricitional force (magnitude f ) is only included in the net force parallel to the surface. The other two are the parallel components of the box's weight (mag. w ) and the pulling force (mag. p)

The box is moving at constant speed, so there is no acceleration and the box is in equilibrium. By Newton's second law,

∑ F = p cos(20º) - w sin(30º) - f = 0

We're given p = 75 N, and

w = m g = (25 kg) (9.80 m/s²)

so

f = (75 N) cos(20º) - (25 kg) (9.80 m/s²) sin(30º)

f ≈ -52 N

That the magnitude is negative makes me think there's a mistake in the question.

13cm

step-by-step explanation:

(apex)

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3