The number of employees per department are normally distributed with a population standard deviation of 198 employees and an unknown population mean. If a random sample of 22 departments is taken and results in a sample mean of 1460 employees, find the error bound (EBM) of the confidence interval with a 80% confidence level.

EBM = +-54.126

Step-by-step explanation:

In this question we have confidence interval to be 80%

The formula to solve this is in the attachment.

Bar X = 1460

Z-alpha/2 = 1.282

Sd = standard deviation = 198 employees

n = 22 departments

After we have inserted all values in to the formula we have:

1460 +-(1.282*198/√22)

= 1460+-(54.12604)

= (1405.87, 1514.126)

The error bounded mean EBM

= +-z-alpha/2 x (sd/√n)

= 1.282 x 198/√22

= 1.282 x 42.22

EBM = +-54.126

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

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step-by-step explanation:

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