The smallest exterior angle of a polygon is 40degrees the largest exterior angle is 80 degrees a) what is the smallest possible number of sides b) what is the largest possible number of sides

a) The smallest possible number of sides of the polygon is a regular polygon with 5 sides

b) The largest possible number of sides of the polygon is a regular polygon with 9 sides

Step-by-step explanation:

a) The smallest exterior angle of the polygon = 40°

The largest exterior angle of the polygon = 80°

Therefore, we have the interior angles are;

The smallest interior angle of the polygon = 180° - 40° = 140°

The largest interior angle of the polygon = 180° - 80° = 100°

Therefore, we have

The interior angles of a regular polygon are given by the following formula;

For an interior angle of 100°, we have;

100/180 × n = n - 2

2 = n - 100/180 × n = 4/9·n

2 = 4/9·n

n = 18/4 = 4.5

Therefore, given that a square has an interior angle of 90° we have the smallest possible number of sides polygon = 5 sides

b) For 140°, we have;

140/180 × n = n - 2

2 = n - 140/180 × n = 2/9·n

2 = 2/9·n

n = 18/2 = 9

n = 9 sides

Therefore, the largest possible number of sides = 9 Sides.