2. If mZ1 = 71 degrees, find the measure of the other 7 angles.

The measure of the other 7 angles are;

m∠2 = m∠3 = 109°; m∠4 = m∠5 = m∠8  = 71°;  m∠6 = m∠7 = 109°

We are given;

m∠1 = 71°

Thus;

m∠1 and m∠2 are angles that form a straight line and as such they are supplementary angles and sum up to 180°

Thus; m∠1 + m∠2 = 180°

71 + m∠2 = 180°

m∠2 = 180 - 71

m∠2 = 109°

Now, m∠2 and m∠3 are alternate angles and as such;

m∠2 =  m∠3

Thus; m∠3 = 109°

Similarly,

m∠1 and m∠4 are alternate angles and as such;

m∠1 =  m∠4

Thus;

m∠4 = 71°

m∠1 and m∠5 are corresponding angles and as such;

m∠1 =  m∠5

Thus;

m∠5 = 71°

m∠2 and m∠6 are corresponding angles and as such;

m∠2 = m∠6

Thus;

m∠6 = 109°

Similar to how angles were gotten earlier, we can say that;

m∠5 = m∠8  = 71°

and m∠6 = m∠7 = 109°

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for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

50x5=$250

step-by-step explanation: