A student has to take two quizzes tomorrow. He has only enough time to study for one of them. The history quiz has 5 true or false questions. The science quiz has 3 multiple choice questions.

Option B is correct.

Miguel should study for the Science quiz as he will do worse in that quiz by guessing.

Step-by-step explanation:

Miguel has to take two quizzes

1) 4 true or false questions on History with a 0.5 chance of acing the quiz

Expected number of correct questions = np

n = number of questions

p = probability of acing the test

Expected number of correct questions = 4 × 0.5 = 2

2) 3 multiple choice questions on Science with a 0.2 chance of acing the quiz.

Expected number of correct questions = 0.2 × 3 = 0.6

It is evident that guessing would yield a worse result in the Science quiz with less than 1 question expected to be correct than history, where he is still expected to get 2 questions correctly by guessing.

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

sure i'm up for it

step-by-step explanation: