Please help me idk how to do this

y = 2(x-2)^2+5

Step-by-step explanation:

Vertex form is y - h = a ( x - k ) ^ 2, where (h,k) is the vertex.

the vertex of the quadratic function is (2,5)

Plug the numbers into the equation which gives you y - 5 = a( x-2)^2

Bring over the five and you have y = a(x-2)^2 +5

That narrows down your options to two answers. The graph opens upward, so the value of a is positive. That leaves one option y = 2(x-2)^2+5.

in geometry, parallel lines are lines in a plane which do not meet; that is, two lines in a plane that do not intersect or touch each other at any point are said to be parallel. by extension, a line and a plane, or two planes, in three-dimensional euclidean space that do not share a point are said to be parallel.

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: