Which is the equatio of a line that has a slope of -2/3 and passes through point (-3,-1)?
y=-2/3x+1
y=-2/3x3
y=-2/3x-1
y =-2/3x-3

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true