The roof of the house is to extend
up 12 feet above the
ceiling, which is 32 feet
across, forming
isosceles triangle. Find
the length of one side of
the roof.

  124.1 feet

An isosceles triangle is one which has two equal sides and two equal angles.

Area of triangle = ab SinC where a and b are the sides, and C is the given included angle.

From the given question, a = b = 18 feet and C = 50°.

Then, Area of this part of the roof =  x 18 x 18 x Sin 50°

                                                =  x 18 x 18 x 0.7660

                                               = 162 x 0.7660

                                             = 124.092

The area of this part of the roof is 124.1 feet.

Step-by-step explanation:

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