Find a 20 in the arithmetic sequence: 5, 12, 19, 26...

the arithmetic sequence is 7

Step-by-step explanation:

let

5 be t1, 12 be t2, 19 be t3 and 26 be t4

t2-t1=d

therefore 12-5=7

t3-t2=d

therefore 19-12=7

t4-t3=d

therefore 26-19=7

the difference is 7

i am not sure please conform it from other sorce

i hope it helps

the answer is simply just 6n add the two together as they have an n

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w