I don't know how to get started on this sums and difference expression: sin θ - √︎3 cos θ =1

We are given:

Sinθ - √3 Cosθ = 1

Solving for θ:

dividing both the sides by 2

1/2 Sinθ - √3/2 Cosθ = 1/2

Cos(60°)*Sinθ - Sin(60°)Cosθ = Sin(30°)                                                               [Since Cos(60°) = 1/2   and   Sin(60°)=√3/2]

We can see that the LHS resembles the formula:

Sin(A - B) = SinACosB - SinBCosA

Sin(θ - 60°) = Sin(30°)

So, we can say that:

θ - 60 = 30

θ = 90°  or   π/4 radians

deez nu tz

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right