Two cyclists are 7 miles apart when they begin biking away from each other in opposite directions. The speed of the first cyclist is 12 miles per hour. The speed of the second cyclist is b miles per hour greater than the speed of the first cyclist. How many miles does the second cyclist bike in 45 minutes?

The distance covered by the second cyclist in 45 minutes is (3/4·b + 9) miles

Step-by-step explanation:

The given parameters are;

The distance between the two cyclist when they begin biking away from each other = 7 miles

The first cyclist's speed = 12 miles per hour

The second cyclist's speed = 12 + b miles per hour

Therefore, we have;

The equation for distance covered, d = Speed × Time

The distance covered by the second cyclist in 45 minutes, is given as follows;

45 minutes = 3/4 hour

 = (12 + b) × 3/4 = (3/4·b + 9) miles

The distance covered by the second cyclist in 45 minutes = (3/4·b + 9) miles.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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