A number cube was rolled as part of an experiment. The results are displayed in the table below. Number 1 2 3 4 5 6 Frequency 4 6 5 7 3 5 What is the best explanation of how to find the experimental probability of rolling a 3? To find the experimental probability of rolling a three, write a ratio of the number of times three occurs to the total number of trials. Simplify if necessary. To find the experimental probability of rolling a three, write a ratio of the total number of trials to the frequency of the number three. Simplify if necessary. To find the experimental probability of rolling a three, write a ratio of the number three to the total number of trials. Simplify if necessary. To find the experimental probability of rolling a three, write a ratio of the total number of trials to the number three. Simplify if necessary.

the answer is C

give the comments brainlest

Step-by-step explanation:

The answer is A. To find the experimental probability of rolling a three, write a ratio of the number of times three occurs to the total number of trials. Simply if necessary.

Step-by-step explanation:

I am currently taking the quiz. I will edit and say if it is correct once I submit it. :)

Edit: I submitted the quiz, and I got a 100! So yes, A. Is the correct answer!

Anyways, I hope this helped! Have a fantastic day! <3

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step-by-step explanation:

i hope this : )

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.