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Mathematics, 21.06.2019 19:50
Prove (a) cosh2(x) β sinh2(x) = 1 and (b) 1 β tanh 2(x) = sech 2(x). solution (a) cosh2(x) β sinh2(x) = ex + eβx 2 2 β 2 = e2x + 2 + eβ2x 4 β = 4 = . (b) we start with the identity proved in part (a): cosh2(x) β sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 β sinh2(x) cosh2(x) = 1 or 1 β tanh 2(x) = .
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Mathematics, 21.06.2019 20:00
Will possibly give brainliest and a high rating. choose the linear inequality that describes the graph. the gray area represents the shaded region. 4x + y > 4 4x β y β₯ 4 4x + y < 4 4x + y β₯ 4
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Mathematics, 22.06.2019 01:30
Fill in the missing exponents in each box and show how you found the answer. (4 points: 2 points for each correct answer with work shown) c. (9^4)^? =9^1 d.(5^? )^3=5^1 *question marks represent the boxes
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Mathematics, 22.06.2019 01:30
Atriangle has side lengths of x, x+11, and 3x+5. what is the perimeter? question 1 options: 3x2+38x+55 3x3+38x2+55x 5x+16 4x+16
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1/3x+2/3(x-24)=1/6x-6...
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