If I have a circle that is 12 in in diameter and it's cold and a half and then folded in half again what is the area of the resulting shape and what is how do I write out the equation

Step-by-step explanation:

Step one:

given data

diameter of circle= 12 in

the radius is r=d/2=6in

the area of the circle is

A=πr^2

A=3.142*6^2

A=3.142*36

A=113.1in^2

If the circle is folded in half, the area will be A/2= 113.1/2= 56.55in^2

In the corresponding shape is folded again the area is A/4= 28.3in^2

The expression for the last shape is

A= πr^2/4

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option