13.El área de un terreno rectangular es de 24 m2. Si el largo mide 2 m más que el ancho. A=24 m2 a) ¿Qué ecuación cuadrática resuelve el problema? b) ¿Cuáles son sus dimensiones? Largo= Ancho=

Area = L · A = 24 m²

L = A + 2

reemplazamos:

(A + 2) · A = 24

A² + 2A - 24 = 0   ⇒ esta es la ecuacion quadratica

la solucion es: (A + 6) · (A - 4)

largo = 6 metros

ancho = 4 metros

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180