Find three consecutive even integers suche
that one half of their sum is between 15
and 21.

9514 1404 393

  10, 12, 14   and maybe {8, 10, 12} and {12, 14, 16}, depending on the meaning of the question

Step-by-step explanation:

If x is the middle one, then their sum is 3x. You want ...

  15 < 3x/2 < 21 . . . . assuming "between 15 and 21" does not include 15 or 21

  30 < 3x < 42

  10 < x < 14

The only even integer in that range is 12, so the three integers are ...

  10, 12, 14 . . . . . half their sum is 18

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We have used <, rather than ≤ in the above solution. This assumes that "between" does not include the values at the end of the range. If those values are included, then two additional solutions are possible: {8, 10, 12} and {12, 14, 16}. For the first set, the half-sum is 15; for the second set, the half-sum is 21.

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step-by-step explanation: