State whether the triangles could be proven congruent, if possible, by SSS or SAS. Include a congruency statement for all congruent triangles.

The congruence theorems that can be used for each of the given pair of triangles are;

1) SSS

2) SAS

3)SAS

4) SSS

5) SAS

6) SAS

1) From the image we see that;

FY ≅ CW  

FP ≅ CM  

YP ≅ MW

This means that 3 corresponding sides of the 2 triangles are congruent and as such it means  ΔMCW ≅ ΔFPY using the Side-Side-Side (SSS) congruency theorem.

2) From the image we see that;

∠CBD and ∠BCA are both alternate interior angles and are therefore congruent. Thus;

∠CBD ≅ ∠BCA

Also, we see that;

EB ≅ EC

DB ≅ CA

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;

ΔBED ≅ ΔAEC using the Side-Angle-Side (SAS) congruency theorem.

3) From the image, we see that;

∠SVU ≅ ∠SVT

Using reflexive property, the shared sides give;

SV ≅ SV  

VT ≅ VU

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;

ΔVSU ≅ ΔVST using Side-Angle-Side (SAS) congruency theorem.

4) From the image, we see that;

MN ≅ QP

MQ ≅ NP

Using reflexive property, the shared sides give;

NQ ≅ NQ

This means that 3 corresponding sides of the 2 triangles are congruent and as such it means  ΔQNM ≅ ΔQNP using the Side-Side-Side (SSS) congruency theorem.  

5) From the image, we see that;

GL ≅ HL

GJ ≅ HK  

∠JLG and ∠HLK are vertically opposite angles and as such;

∠JLG ≅ ∠HLK

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;  

ΔQNM ≅ ΔQNP using Side-Angle-Side (SAS) congruency theorem.

6) We observe from the given triangles that;

∠XZY ≅ ∠XZW (They are both right angles = 90°)

Using reflexive property, the shared side is congruent to itself and so;

XZ ≅ XZ  

Also;

ZW ≅ ZY

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;  

ΔXYZ ≅ ΔXWZ  using Side-Angle-Side (SAS) congruency theorem.

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1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29