Which equation is perpendicular to the graph of 5x - 3y = 12

y = -3/5x + c

Step-by-step explanation:

Re-arrange the initial equation so that the it becomes y =

To do this, you +3y on both sides to get 5x = 3y + 12

And then -12 on both sides to get 5x - 12 = 3y

Divide everything by 3 so you get 5/3x - 4 = y OR y = 5/3x - 4

The gradient of the initial equation is 5/3, to find the perpendicular line, you need the negative reciprocal of it, which is -3/5

Therefore your perpendicular line should be y = -3/5x + c

Because you didn't specify on what point they intersect, i can't find c for you.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

6/20

step-by-step explanation: