1.) Use the following information to solve the questions. Kay sold 200 tickets for her school auction. Adult tickets cost $8 and child tickets cost
$5. Kay collected $1,225 in all. How many tickets did Kay sell?
8
5
200
O 1,225

9514 1404 393

Step-by-step explanation:

Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...

  8a +5(200 -a) = 1225

  3a = 225 . . . . . . . . . . subtract 1000, simplify

  a = 75 . . . . . . . . . . . . .divide by 3

  200 -a = 125

75 adult ($8) and 125 child ($5) tickets were sold.

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Additional comment

The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.

y=-2x+1500

step-by-step explanation:

+1500

2 over one

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.