A particle moves on the circle x2+y2=25 x 2 + y 2 = 25 in the xy x y -plane for time t≥0 t ≥ 0 . At the time when the particle is at the point (3,4) ( 3 , 4 ) , dxdt=6 d x d t = 6 . What is the value of dydt d y d t at this time?

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

Not sure what the question is?