CAN SOMEONE PLEASE HELP WILL GIVE BRAINLIEST

c = 7

d = 5

Step-by-step explanation:

Notice that in the first expression, x^c is inside a square root, and only perfect squares can be extracted from it. On the simplified form shown on the right hand side, we have x^3 outside the root and a single "x" left inside. In order for such to happen (x^3 get outside the root) there must have been an x^6 inside the square root. This together with the sole "x" that was left in the root, totals seven factors of x that should have been originally inside the square root:

x^6 * x = x^7  therefore c was a "7"

In the second expression we have a CUBIC root, so only perfect cubes can get extracted from it. Since there is one factor "x" shown in the simplified form (right hand side of the equal sign), that means that it must have been an x^3 (perfect cube) apart from the x^2 that was left inside the root. This makes the original power of x to be a 3 + 2 = 5.

Therefore d = 5

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length