PLEASE HELP ITS ALREADY LATE A trucks position relative to a cars position is -60 feet. The car and the truck move in the same direction , but the car moves 5 feet per second faster for 8 seconds. What operations could be used to find the trucks relative position after 8 seconds. EXplain

The truck's relative position with respect to the car is: -100 feet

Step-by-step explanation:

If the truck is moving at a seed "V" then its position after 8 seconds is going to be:

XT = V* t = V * 8 = 8 V

The car, which is initially 60 feet ahead of the truck and starts moving at 5 m/s faster than the truck, would have a speed given by: V + 5

And its position (relative to the truck's) would be:

XC = 60 + (V + 5) * t = 60 + (V + 5) * 8 = 60 + 40 + 8 V = 100ft + 8 V

then the position of the truck relative to that of the car would be given by the difference:

XT - XC = 8 V - (100 +8 V) = 8 V - 8 V - 100ft = -100 feet

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step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.