Sample problem 1. A 1000.0 kg truck is traveling at an acceleration of 4.5000 m/s2, East. Find
the net force needed to accelerate the truck.
Given: a = 4.5000 m/s2, East
m= 1000.0 kg
Find ΣΕ. .
Solution:
F = mã

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p