Mathematics, 05.11.2020 21:20 gagem1278

An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different times. After 4 hours, they are 4 00 miles apart. Which system of linear equations can be used to determine the time that each of the trains has been traveling?

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Answer from: ScarySkyler5571

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 Equation 1

95 E + 110W = 400 Equation 2

Hence,

An Eastbound train has been travelling for = (E) = 2.67 hours

A Westbound train has been travelling for = (W) = 1.33 hours

Step-by-step explanation:

An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different times. After 4 hours, they are 4 00 miles apart. Which system of linear equations can be used to determine the time that each of the trains has been traveling?

Speed = Distance/Time

Distance = Speed × Time

Let the time

An Eastbound train = (E)

A Westbound train = (W)

E + W = 4 hours Equation 1

95mph × E + 110mph × W = 400 miles

95 E + 110W = 400 miles Equation 2

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 Equation 1

95 E + 110W = 400 Equation 2

E = 4 - W

We substitute 4 - W for E in Equation 2

95 (4 - W) + 110W = 400

380 - 95W + 110W = 400

Collect like terms

95W - 110W = 400 - 380

15W = 20

W = 20/15

W = 1.3333333333 hours

≈ 1.33 hours

E = 4 - W

E = 4 - 1.33 hours

E = 2.67 hours

Therefore,

An Eastbound train has been travelling for = (E) = 2.67 hours

A Westbound train has been travelling for = (W) = 1.33 hours

Answer from: Quest

l.ln.lln.k.nkl

step-by-step explanation:

Answer from: Quest

c. x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

$\frac{little}{big} =\frac{side mn}{side ab}=\frac{side on}{side cb}$ .

$\frac{0.96}{1.2}=\frac{x}{3}$

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

$0.96(3)=1.2(x)\\2.88=1.2x\\\frac{2.88}{1.2}=\frac{1.2x}{1.2} \\2.4=x$

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