Shelley has a collection of dimes, nickels and quarters that is worth $5.25. There are a total of 48 coins. If there are 7 more nickels than quarters, how many dimes are there?

25 dimes

Step-by-step explanation:

Given

Coins: Nickels (N), Quarters (Q) , and Dimes (D)

$0.05 = 1 nickel, $0.10 = 1 dime  and $0.25 = 1 quarter

So, the amount implies:

The number of coin implies:

and

Required

Determine the number of Dimes

Substitute 7 + Q for N in the first and second equation

Collect Like Terms

----- (1)

Collect Like Terms

Make Q the subject

Substitute 20.5 - 0.50D for Q in  (1)

Solve for D

Hence, there are 25 Dimes

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

2x^2+5x+17

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