Consider random samples of size 900 from a population with proportion 0.65 . Find the standard error of the distribution of sample proportions.

The value is

Step-by-step explanation:

From the question we are told that

   The sample size is  n  =  900

    The population proportion is  

Generally the standard error of the distribution of sample proportion is mathematically represented as

=>    

=>    

step-by-step explanation:

i hate black

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!