PLEASE HELP What is the common difference of the sequence with the recursive
rule f(1)= 4; f(n) = f(n-1) + 5 ?

5

Step-by-step explanation:

it can be found in two ways

f(n)-f(n-1) is common difference of the sequence.

knowing f(n) = f(n-1) + 5

f(n)-f(n-1)=5

so 5 is difference of the sequence.

other method is

f(1)=4

f(2)=?

f(n)=f(n-1)+5 n=2

f(2)=f(2-1)+5

f(2)=f(1)+5

f(2)=4+5=9

f(2)-f(1)=9-4=5

so 5 is difference of the sequence.

what are ur choices?