The distribution of rhesus monkey tail lengths can be approximated by N(6.8, 0.44). Both mean and standard deviation are given in centimeters. What is the cutoff value for the 80th percentile. In other words, 80% of tail lengths are less than what value?

7.17 cm

Step-by-step explanation:

Given that :

Mean (m) = 6.8 cm

Standard deviation (s) = 0.44 cm

Cut off value for the 80th percentile :

The cut off value :

From ;

Zscore = (x - m) / s

x = cut off value

Zscore corresponding to 80%(0.8) = 0.842 (from z probability calculator)

Plugging into our formula :

0.842 = (x - 6.8) / 0.44

0.842 * 0.44 = x - 6.8

0.37048 = x - 6.8

0.37048 + 6.8 = x

7.17048 = x

X = 7.17 cm

answer: idk

step-by-step explanation:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.