Animals in an experiment are to be kept under a strict diet. Each animal should receive 50 grams of protein and 12 grams of fat. The laboratory technician is able to purchase two food mixes: Mix A has 10% protein and 8% fat; mix B has 50% protein and 5% fat. How many grams of each mix should be used to obtain the right diet for one animal?

100 grams of A mixed with 80 grams of B will provide the daily diet for a single animal.

Step-by-step explanation:

Step 1

The requirement for each animal is given as 50g of protein  and 12g of fat

let mix A  be represent as   containing  0.10A protein and 0.08A fat

and mix B be represented as containing 0.5B protein and 0.05B  fat

Therefore for Protein , we have   0.10A + 0.5B= 50 Equation 1

And for fat , we have   0.08A + 0.05B= 12Equation 2

Step 2-- Solving

0.10A + 0.5B= 50 Equation 1

0.08A + 0.05B= 12Equation 2

multiplying equation 1 by 10 and equation 2 by 100 we have

1A+ 5B=500Equation 3

8A+ 5B= 1200Equation 4

Subtracting equation 3 from equation 4

7A= 700

A = 700/7= 100

Puting value of A = 100 IN  EQUATION 3

1(100) + 5B= 500

5B= 500-100

B=400/5= 80

Therefore 100 grams of A mixed with 80 grams of B will provide the daily diet for a single animal.

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step-by-step explanation:

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this